The order of osmotic pressures of equimolar solutions of BaCl2, NaCl and glucose will be

Question

The order of osmotic pressures of equimolar solutions of BaCl2, NaCl and glucose will be (A)  BaCl2 > NaCl > glucose (B)  NaCl >BaCl2 > glucose (C) glucose > BaCl2 > NaCl  (D) glucose > NaCl > BaCl2

Tardigrade Admin · Accepted Answer

Glucose is an organic compound and this is not ionised while

B a C l_{2}

and

N a Cl

are inorganic compounds and they are strong electrolytes and are normally

100%

ionised at normal dilution.

B a C l_{2} ⇌ B a^{2 +} + 2 C l^{-}

N a Cl ⇌ N a^{+} + C l^{-}

∵

Osmotic pressure is a colligative property and hence, depends on the number of ions.
So, decreasing order of osmotic pressure is

B a C l_{2} > N a Cl >

glucose

Q. The order of osmotic pressures of equimolar solutions of $B a C l_{2},$ $N a Cl$ and glucose will be

$B a C l_{2} > N a Cl >$ glucose

$N a Cl > B a C l_{2} >$ glucose

glucose $> B a C l_{2} > N a Cl$

glucose $> N a Cl > B a C l_{2}$

Q. The order of osmotic pressures of equimolar solutions of BaCl2​, NaCl and glucose will be

BaCl2​>NaCl> glucose

NaCl>BaCl2​> glucose

glucose >BaCl2​>NaCl

glucose >NaCl>BaCl2​

Q. The order of osmotic pressures of equimolar solutions of $B a C l_{2},$ $N a Cl$ and glucose will be

$B a C l_{2} > N a Cl >$ glucose

$N a Cl > B a C l_{2} >$ glucose

glucose $> B a C l_{2} > N a Cl$

glucose $> N a Cl > B a C l_{2}$