The order of melting point of ortho, para, meta-nitrophenol is

Question

The order of melting point of ortho, para, meta-nitrophenol is (A)  o > m > p  (B)  p > m > o  (C)  m > p > o  (D)  p > o > m

Tardigrade Admin · Accepted Answer

Due to intra molecular hydrogen bonding in ortho-isomer, it has least m.p. Due to effective intermolecular hydrogen bonding in para-isomer, it has highest melting point among the isomers. So, the order is

(11 4^{\circ} C) para > (9 7^{\circ} C) meta > (4 5^{\circ} C) ortho

Q. The order of melting point of ortho, para, meta-nitrophenol is

$o > m > p$

$p > m > o$

$m > p > o$

$p > o > m$

Due to intra molecular hydrogen bonding in ortho-isomer, it has least m.p. Due to effective intermolecular hydrogen bonding in para-isomer, it has highest melting point among the isomers. So, the order is
$(11 4^{\circ} C) para > (9 7^{\circ} C) meta > (4 5^{\circ} C) ortho$

Q. The order of melting point of ortho, para, meta-nitrophenol is

o>m>p

p>m>o

m>p>o

p>o>m

Due to intra molecular hydrogen bonding in ortho-isomer, it has least m.p. Due to effective intermolecular hydrogen bonding in para-isomer, it has highest melting point among the isomers. So, the order is (114∘C)para​>(97∘C)meta​>(45∘C)ortho​

$o > m > p$

$p > m > o$

$m > p > o$

$p > o > m$

Due to intra molecular hydrogen bonding in ortho-isomer, it has least m.p. Due to effective intermolecular hydrogen bonding in para-isomer, it has highest melting point among the isomers. So, the order is
$(11 4^{\circ} C) para > (9 7^{\circ} C) meta > (4 5^{\circ} C) ortho$