Question

The order of electronegativity of carbon in $sp,s{p}^2$ and $s{p}^3$ hybridised states follows

• A. $sp>s{p}^2>s{p}^3$
• B. $s{p}^3>s{p}^2>sp$
• C. $sp>s{p}^3>s{p}^2$
• D. $s{p}^2>sp>s{p}^3$

Answer 1

Answer: (A)

Electronegativity of carbon is directly proportional to the s-character in hybridised state, i.e. more is the s-character more will be the electronegativity. Thus, the order of electronegativity of carbon will be
$\underset{(50\%s\text{Character})}{\mathrm{sp}}>\underset{(33.3\%s\text{Character})}{s{p}^2}>\underset{(25\%s\text{Character})}{s{p}^3}$