Question

The order of electronegativity of carbon in $sp, sp^{2}$ and $sp^{3}$ hybridised states follows

• A. $sp > sp^{2} > sp^{3}$
• B. $sp^{3} > sp^{2} > sp$
• C. $sp > sp^{3} > sp^{2}$
• D. $sp^{2} > sp > sp^{3}$

Answer 1

Answer: (A)

Electronegativity of carbon is directly proportional to the s-character in hybridised state, i.e. more is the s-character more will be the electronegativity. Thus, the order of electronegativity of carbon will be
$\underset{(50\% \,s \text{Character})}{sp} > \underset{(33.3\% \,s \text{Character})}{sp^2} > \underset{(25\% \,s \text{Character})}{sp^3}$