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Tardigrade
Question
Chemistry
The orbital configuration oi 24Cr is 3d5 4s1. The number of unpaired electrons in Cr3+ (g) is
Q. The orbital configuration oi
24
C
r
is
3
d
5
4
s
1
. The number of unpaired electrons in
C
r
3
+
(
g
)
is
2458
189
Structure of Atom
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A
3
45%
B
2
19%
C
1
21%
D
4
15%
Solution:
C
r
3
+
has configuration
3
d
3
4
s
0