1. Tardigrade
  2. Question
  3. Chemistry
  4. The orbital configuration oi 24Cr is 3d5 4s1. The number of unpaired electrons in Cr3+ (g) is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The orbital configuration oi $_{24}Cr$ is $3d^5 4s^1$. The number of unpaired electrons in $Cr^{3+} (g)$ is

Structure of Atom

Solution:

$Cr^{3+}$ has configuration $3d^3\, 4s^0$