Question

The orbital angular momentum of an electron in $2s$ -orbital is

• A. $+\frac{1}{2}\frac{h}{2\pi }$
• B. zero
• C. $\frac{h}{2\pi }$
• D. $\sqrt{2}\frac{h}{2\pi }$

Answer 1

Answer: (B)

Orbital angular momentum
$=\sqrt{l(l+1)}\cdot \frac{h}{2\pi }$
for $2s$-orbital, $l=0$
$\therefore$ Orbital angular momentum
$=\sqrt{0(0+1)}\frac{h}{2\pi }$
$=$ zero