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Q. The orbital angular momentum of an electron in $ 2s $ -orbital is

WBJEEWBJEE 2007

Solution:

Orbital angular momentum
$=\sqrt{l(l+1)} \cdot \frac{h}{2 \pi}$
for $2 s$-orbital, $l=0$
$\therefore $ Orbital angular momentum
$=\sqrt{0(0+1)} \frac{h}{2 \pi}$
$=$ zero