Question

The orbital angular momentum of a p-electron is given as

• A. $\frac{h}{\sqrt{2}\pi }$
• B. $\sqrt{3}\frac{h}{2\pi }$
• C. $\sqrt{\frac{3}{2}}\frac{h}{\pi }$
• D. $\sqrt{6}\frac{h}{2\pi }$

Answer 1

Answer: (A)

Orbital angular momentum $(m)$
$=\sqrt{l(l+1)}\frac{h}{2\pi }$
For $p$-electron; $l=1$
Thus, $m=\sqrt{1\left(1+1\right)}\frac{h}{2\pi }=\frac{\sqrt{2}h}{2\pi }=\frac{h}{\sqrt{2}\pi }$