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Q. The orbital angular momentum of a p-electron is given as

JIPMERJIPMER 2013Structure of Atom

Solution:

Orbital angular momentum $(m)$
$ = \sqrt{l(l+1)} \frac{h}{2 \pi}$
For $p$-electron; $l = 1$
Thus, $m = \sqrt{1\left(1+1\right)} \frac{h}{2\pi}= \frac{\sqrt{2}h}{2\pi} = \frac{h}{\sqrt{2}\pi}$