Q. The orbital angular momentum for an electron revolving in an orbit is given by $(l + 1) \frac{h}{2 π}$ . This momentum for an s-electron will be given by:

1804 201 AIEEEAIEEE 2003Structure of Atom Report Error

A

$+ \frac{1}{2} \cdot \frac{h}{2 π}$

3%

B

zero

14%

C

$\frac{h}{2 π}$

72%

D

$2 \cdot \frac{h}{2 π}$

10%

Solution:

For s-electron, $l = 0$