Question

The $ONO$ angle is maximum in

• A. $N{O}_3^{-}$
• B. $N{O}_2$
• C. $N{O}_2^{-}$
• D. $N{O}_2^{+}$

Answer 1

Answer: (D)

The bond angle is maximum in $N{O}_2^{+}\left(180^{\circ }\right)$.
$N{O}_3^{-}$-In $N{O}_3^{-},N$ atom undergo $s{p}^2$-hybridisation. Each oxygen atom also has $s{p}^2$-hybridisation.
The ion has trigonal planar geometry with bond angle $120^{\circ }$.

NO ${}_2^{2-}-$ It has angular geometry $(s{p}^2$ hybridisation) due to presence of lone pair of electron on $N$ atom. Bond angle $116^{\circ }$.
$N{O}_2$-It has angular geometry
( $s{p}^2$ hybridisation), bond angle $134^{\circ }$.
$N{O}_2^{+}$-Nitronium ion has linear structure
(sp hybridisation) with bond angle $180^{\circ }$.