Question

The ONO angle is maximum in

• A. ${\text{NO}}_3^{-}$
• B. ${\text{NO}}_2^{-}$
• C. $N{O}_2$
• D. ${NO}_2^{+}$

Answer 1

Answer: (D)

In $N{O}_3^{-},N$ atom undergoes $s{p}^2-$ hybridisation. Thus, the ion has trigonal planar geometry with bond angle $120^{\circ }C$.

$N{O}_2^{-}$ has angular geometry ( $s{p}^2$ hybridisation) due to presence of one lone pair of electrons on $N$ atom. Bond angle is $116^{\circ }.N{O}_2$ has angular geometry ( $s{p}^2$ hybridisation) with bond angle $134^{\circ }$ $N{O}_2^{+}$ (nitronium ion) has linear structure (sp hybridisation) with bond angle $180^{\circ }.$

$\therefore$ The bond angle is maximum in $N{O}_2^{+}$, ie, $180^{\circ }$.