The only cations present in a slightly acidic solution are Fe3+,Zn2+ and Cu2+ The reagent that when added in excess to this solution would identify and separate Fe3+ in one step is

Question

The only cations present in a slightly acidic solution are Fe3+,Zn2+ and Cu2+ The reagent that when added in excess to this solution would identify and separate Fe3+ in one step is (A)  2M HCl  (B)  6M NH3  (C)  6M NaOH  (D)  H2S gas

Tardigrade Admin · Accepted Answer

Cupric ion reacts with excess of ammonia solution to give a deep blue color of tetra ammine cupric ion.

C u^{2 +} + 4 N H_{4} O H \to Deep blue color [C u (N H_{3}) 4]^{2 +} + 4 H_{2} O

Z n

(II) ions react with ammonia to form white gelatinous

ppt

of

Z n (O H)_{2}

which is soluble in excess ammonia.

Z n^{2 +} + 2 N H_{3} + 2 H_{2} O \to Z n (O H)_{2} ↓ + 2 N H_{4}^{+}

Z n (O H) ↓ 4 N H_{3} \to [Z n (N H_{3})_{4}]^{2 +} + 2 O H^{-}

When the above reactions are not observed,

F e^{3 +}

ion is confirmed.

Q. The only cations present in a slightly acidic solution are $F e^{3 +}, Z n^{2 +}$ and $C u^{2 +}$ The reagent that when added in excess to this solution would identify and separate $F e^{3 +}$ in one step is

$2 M H Cl$

$6 M N H_{3}$

$6 M N a O H$

$H_{2} S g a s$

Q. The only cations present in a slightly acidic solution are Fe3+,Zn2+ and Cu2+ The reagent that when added in excess to this solution would identify and separate Fe3+ in one step is

2MHCl

6MNH3​

6MNaOH

H2​Sgas

Q. The only cations present in a slightly acidic solution are $F e^{3 +}, Z n^{2 +}$ and $C u^{2 +}$ The reagent that when added in excess to this solution would identify and separate $F e^{3 +}$ in one step is

$2 M H Cl$

$6 M N H_{3}$

$6 M N a O H$

$H_{2} S g a s$