Question

The $[OH{]}^{-}$in a solution is $1mol{L}^{-1}$. The $pH$ of the solution is

• A. 1
• B. 0
• C. 14
• D. $10^{-14}$

Answer 1

Answer: (C)

Given, $\left[O{H}^{-}\right]=1mol{L}^{-1}$
So, we know that
$pOH=-\log \left[O{H}^{-}\right]$
$pOH=-\log 1=0$
$\because pH+pOH=14$
$\therefore pH=14-0=14$