The numerically greatest term in the binomial expansion of (2a - 3b)19 and a = (1/4) and b = (2/3) is

Question

The numerically greatest term in the binomial expansion of (2a - 3b)19 and a = (1/4) and b = (2/3) is (A) 19C5 . 211 (B) 19C3 . (1/211) (C) 19C4 . (1/213) (D) 19C3 . 213

Tardigrade Admin · Accepted Answer

Correct answer is (d) 19C3 . 213

Q. The numerically greatest term in the binomial expansion of $(2 a - 3 b)^{19}$ and $a = \frac{1}{4}$ and $b = \frac{2}{3}$ is

$^{19} C_{5} . 2^{11}$

$^{19} C_{3} . \frac{1}{2 ^{11}}$

$^{19} C_{4} . \frac{1}{2 ^{13}}$

$^{19} C_{3} . 2^{13}$

Correct answer is (d) $^{19} C_{3} . 2^{13}$

Q. The numerically greatest term in the binomial expansion of (2a−3b)19 and a=41​ and b=32​ is

19C5​.211

19C3​.2111​

19C4​.2131​

19C3​.213