The numbers of lone pair (s) on Xe in XeF2 and XeF4 are, respectively

Question

The numbers of lone pair (s) on Xe in XeF2 and XeF4 are, respectively (A) 2 and 3 (B) 4 and 1 (C) 3 and 2 (D) 4 and 2

Tardigrade Admin · Accepted Answer

As Xe has eight valence electrons. In XeF2, Xe forms 2 bonds with fluorine thus 6 electrons remains unbonded. So, it has 3 lone pairs. While in XeF4, Xe form 4 bonds with fluorine, thus 4 electrons remain unbonded. Thus, it has 2 lone pairs.

Q. The numbers of lone pair (s) on $X e$ in $X e F_{2}$ and $X e F_{4}$ are, respectively

2 and 3

4 and 1

3 and 2

4 and 2

As $X e$ has eight valence electrons. In $X e F_{2}$ , $X e$ forms $2$ bonds with fluorine thus $6$ electrons remains unbonded. So, it has $3$ lone pairs. While in $X e F_{4}$ , $X e$ form $4$ bonds with fluorine, thus $4$ electrons remain unbonded. Thus, it has $2$ lone pairs.

Q. The numbers of lone pair (s) on Xe in XeF2​ and XeF4​ are, respectively