Question

The numbers of $H^{+}$ ions present in $1mL$ of a solution whose pH is $13$

• A. $6.022\times 10^{10}$
• B. $6.022\times 10^7$
• C. $6.022\times 10^{20}$
• D. $6.022\times 10^{23}$

Answer 1

Answer: (B)

pH= 13·
$\Rightarrow [H{]}^{+}=10^{-13}mol{L}^{-1}$
$\Rightarrow 1000ml$ solution contains
$10^{-13}\times 6.022\times 10^{23}{H}^{+}ions$
$=6.022\times 10^{10}{H}^{+}ions$
$\therefore$ 1 ml solution contains
$\frac{6.022\times 10^{10}}{1000}{H}^{+}ions$
$=6.022\times 10^7{H}^{+}ions$