Since, 1000000 is a 7-digit number and the number of digits to be used is also 7. Therefore, the numbers to be counted will be 7 digit only. Also, the numbers have to be greater than 1000000 , so they can begin either with 1,2 or 4.
The number of numbers beginning with 1=3!2!6!=24×5×6=60 as when 1 is fixed at the extreme left position, the remaining digits to be rearranged will be 0,2,2,2,4,4 in which there are 3,2′s and 2,4′s.
Total numbers begining with 2 =2!2!6!=23×4×5×6=180
and total numbers begining with 4=3!6!=4×5×6=120
Therefore, the required number of numbers =60+180+120=360.
Alternate Method
The number of 7-digit arrangements, clearly, 3!2!7!=420 But this will include those numbers also, which have 0 at the extreme left position. The number of such arrangements 3!2!6! (by fixing 0 at the extreme left position) =60
Therefore, the required number of numbers =420−60=360.