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Question
Mathematics
The number of zero terms in the expansion of (1+3 √2 x)9+(1-3 √2 x)9 is
Q. The number of zero terms in the expansion of
(
1
+
3
2
x
)
9
+
(
1
−
3
2
x
)
9
is
1497
203
Binomial Theorem
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A
2
30%
B
3
28%
C
4
21%
D
5
21%
Solution:
Given expression
=
2
[
1
+
9
C
2
(
3
2
x
)
2
+
9
C
4
(
3
2
x
)
4
<
b
r
/
><
b
r
/
>
+
9
C
6
(
3
2
x
)
6
+
9
C
8
(
3
2
x
)
8
]
∴
the number of non-zero terms is
5