Q.
The number of ways of choosing a committee of two women and three men from five women and six men, if Mr. A refuses to serve on the committee if Mr. B is a member and Mr. B can only serve, if Miss C is the member of the committee is
(I) Miss C is taken
(A) B included ⇒A excluded ⇒4C1×4C2=24
(B) B excluded ⇒4C1×5C3=40
(II) Miss C is not taken ⇒B does not come ⇒4C2×5C3=60 ⇒ Total =124 Alternate method: Case I:
Mr. B is present ⇒A is excluded and C included
Hence, the number of ways is 4C24C1=24. Case II:
Mr. ‘B’ is absent ⇒ No constraint
Hence, the number of ways is 5C35C2=100. ∴ Total =124.