The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21 are distinct, is :

Question

The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21 are distinct, is : (A) 220 (B) 220 - 1  (C) 220 + 1  (D) 221

Tardigrade Admin · Accepted Answer

Q. The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21 are distinct, is :

$2^{20}$

$2^{20} - 1$

$2^{20} + 1$

$2^{21}$

Q. The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21 are distinct, is :

220

220−1

220+1

221

$2^{20}$

$2^{20} - 1$

$2^{20} + 1$

$2^{21}$