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Tardigrade
Question
Mathematics
The number of values of x in the interval ((π/4), (7 π/4)) for which 14 operatornamecosec2 x-2 sin 2 x=21 - 4 cos 2 x holds, is
Q. The number of values of
x
in the interval
(
4
π
,
4
7
π
)
for which
14
cosec
2
x
−
2
sin
2
x
=
21
−
4
cos
2
x
holds, is __________
635
181
JEE Main
JEE Main 2022
Trigonometric Functions
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Answer:
4
Solution:
x
∈
(
4
π
,
4
7
π
)
14
cosec
2
x
−
2
sin
2
x
=
21
−
4
cos
2
x
=
21
−
4
(
1
−
sin
2
x
)
=
17
+
4
sin
2
x
14
cosec
2
x
−
6
sin
2
x
=
17
let
sin
2
x
=
p
p
14
−
6
p
=
17
⇒
14
−
6
p
2
=
17
p
6
p
2
+
17
p
−
14
=
0
p
=
−
3.5
,
3
2
⇒
sin
2
x
=
3
2
⇒
sin
x
=
±
3
2
∴
Total
4
solutions