Q. The number of unpaired electrons in $F e^{3 +} (Z = 26)$ are

2541 219 KCETKCET 2000The d-and f-Block Elements Report Error

A

5

51%

B

6

9%

C

3

28%

D

4

11%

Solution:

Fe(Z = 26): $[A r]^{18} 4 s^{2} 3 d^{6}$
$F e^{3 +} : [A r]^{18} 3 d^{5}$
Number of unpaired electrons = 5.