The number of unpaired electrons in a paramagnetic diatomic molecule of an element with atomic number 16 is

Question

The number of unpaired electrons in a paramagnetic diatomic molecule of an element with atomic number 16 is (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

Like O 2 molecule, sulphur (atomic number =16 ) exists as S 2 molecule in vapour state and it is paramagnetic due to the presence of two unpaired electrons in antibonding π molecular orbitals.

Q. The number of unpaired electrons in a paramagnetic diatomic molecule of an element with atomic number $16$ is

1

2

3

4

Like $O_{2}$ molecule, sulphur (atomic number $= 16$ ) exists as $S_{2}$ molecule in vapour state and it is paramagnetic due to the presence of two unpaired electrons in antibonding $π$ molecular orbitals.

Q. The number of unpaired electrons in a paramagnetic diatomic molecule of an element with atomic number 16 is

1

2

3

4

Like O2​ molecule, sulphur (atomic number =16 ) exists as S2​ molecule in vapour state and it is paramagnetic due to the presence of two unpaired electrons in antibonding π molecular orbitals.

Q. The number of unpaired electrons in a paramagnetic diatomic molecule of an element with atomic number $16$ is

Like $O_{2}$ molecule, sulphur (atomic number $= 16$ ) exists as $S_{2}$ molecule in vapour state and it is paramagnetic due to the presence of two unpaired electrons in antibonding $π$ molecular orbitals.