The number of unit cells in 58.5 g of NaCl is nearly

Question

The number of unit cells in 58.5 g of NaCl is nearly (A) 6 × 1020 (B) 3 × 1022 (C) 1.5 × 1023 (D) 0.5 × 1024

Tardigrade Admin · Accepted Answer

58.5 g NaCl = 1 mole = 6.02 × 1023 Na+Cl- units One unit cell contains 4 Na+Cl- units. Hence number of unit cell present = (6.02× 1023/4) = 1.5 × 1023

Q. The number of unit cells in $58.5 g$ of $N a Cl$ is nearly

$6 \times 1 0^{20}$

$3 \times 1 0^{22}$

$1.5 \times 1 0^{23}$

$0.5 \times 1 0^{24}$

$58.5 g N a Cl = 1$ mole $= 6.02 \times 1 0^{23} N a^{+} C l^{-}$ units
One unit cell contains $4 N a^{+} C l^{-}$ units. Hence number of unit cell present
$= \frac{6.02 \times 1 0 ^{23}}{4} = 1.5 \times 1 0^{23}$

Q. The number of unit cells in 58.5g of NaCl is nearly

6×1020

3×1022

1.5×1023

0.5×1024