The number of turns in the coil of an ac generator is 5000 and the area of the coil is 0.25 m 2 . The coil is rotated at the rate of 100 cycles/s in a magnetic field of 0.2 Wb / m 2. The peak value of the emf generated is nearly

Question

The number of turns in the coil of an ac generator is 5000 and the area of the coil is 0.25 m 2 . The coil is rotated at the rate of 100 cycles/s in a magnetic field of 0.2 Wb / m 2. The peak value of the emf generated is nearly (A) 786 kV (B) 440 kV (C) 220 kV (D) 157.1 kV

Tardigrade Admin · Accepted Answer

e0=ω N B A=(2 π v) N B A =2 × 3.14 × 100 × 5000 × 0.2 × 0.25 =157 kV

Q. The number of turns in the coil of an ac generator is $5000$ and the area of the coil is $0.25 m^{2} .$ The coil is rotated at the rate of $100$ cycles/s in a magnetic field of $0.2 Wb / m^{2}$ . The peak value of the emf generated is nearly

786 kV

440 kV

220 kV

157.1 kV

$e_{0} = ω NB A = (2 π v) NB A$
$= 2 \times 3.14 \times 100 \times 5000 \times 0.2 \times 0.25$
$= 157 kV$

Q. The number of turns in the coil of an ac generator is 5000 and the area of the coil is 0.25m2. The coil is rotated at the rate of 100 cycles/s in a magnetic field of 0.2Wb/m2. The peak value of the emf generated is nearly