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Question
Mathematics
The number of θ ∈(0,4 π) for which the system of linear equations 3( sin 3 θ) x-y+z=2 3( cos 2 θ) x+4 y+3 z=3 6 x+7 y+7 z=9 has no solution is :
Q. The number of
θ
∈
(
0
,
4
π
)
for which the system of linear equations
3
(
sin
3
θ
)
x
−
y
+
z
=
2
3
(
cos
2
θ
)
x
+
4
y
+
3
z
=
3
6
x
+
7
y
+
7
z
=
9
has no solution is :
508
129
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Determinants
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A
6
B
7
C
8
D
9
Solution:
The system of equation has no solution.
D
=
∣
∣
3
sin
3
θ
3
cos
2
θ
6
−
1
4
7
1
3
7
∣
∣
=
0
21
sin
3
θ
+
42
cos
2
θ
−
42
=
0
sin
3
θ
+
2
cos
2
θ
−
2
=
0
Number of solution is 7 in
(
0
,
4
π
)