Let mth term of first A.P. be equal to the nth term of the second A.P. then 2,5,8,....50 terms, series 1 3,5,7,...,60 terms, series 2
common series 5,11,17,...,119 40th term of series 1=59th term of series 2=119 = last term of common series ⇒an=5+(n−1)d⇒119+1=6n⇒n=20. ∴ Number of common terms are 20.