The number of structural and configurational isomers of a bromo compound C 5 H 9 Br obtained by the addition of HBr on 2-pentyne respectively are

Question

The number of structural and configurational isomers of a bromo compound C 5 H 9 Br obtained by the addition of HBr on 2-pentyne respectively are (A) 1,2 (B) 2,4 (C) 4,2 (D) 2,1

Tardigrade Admin · Accepted Answer

CH 3 CH 2- underset text2-PentyneC ≡ C - CH 3 stackrel HBr longrightarrow <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/71f64c0ec37075b1afc86d045fdef01a-.png" /> Thus, each one of these will exist as a pair of geometrical isomer. Structural isomers (position) =2 Stereoisomers =4

Q. The number of structural and configurational isomers of a bromo compound $C_{5} H_{9} B r$ obtained by the addition of $H B r$ on $2 - p e n t y n e$ respectively are

1,2

2,4

4,2

2,1

$C H_{3} C H_{2} - 2-Pentyne C \equiv C - C H_{3} ⟶ H B r$

Thus, each one of these will exist as a pair of geometrical isomer.

Structural isomers (position) $= 2$

Stereoisomers $= 4$

Q. The number of structural and configurational isomers of a bromo compound C5​H9​Br obtained by the addition of HBr on 2−pentyne respectively are

1,2

2,4

4,2

2,1

CH3​CH2​−2-PentyneC≡C​−CH3​⟶HBr​ Thus, each one of these will exist as a pair of geometrical isomer. Structural isomers (position) =2 Stereoisomers =4

Q. The number of structural and configurational isomers of a bromo compound $C_{5} H_{9} B r$ obtained by the addition of $H B r$ on $2 - p e n t y n e$ respectively are

$C H_{3} C H_{2} - 2-Pentyne C \equiv C - C H_{3} ⟶ H B r$

Thus, each one of these will exist as a pair of geometrical isomer.

Structural isomers (position) $= 2$

Stereoisomers $= 4$