Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The number of sp 3 hybridised carbons in an acyclic neutral compound with molecular formula C 4 H 5 N is :
Q. The number of
s
p
3
hybridised carbons in an acyclic neutral compound with molecular formula
C
4
H
5
N
is :
578
131
JEE Main
JEE Main 2022
Organic Chemistry – Some Basic Principles and Techniques
Report Error
Answer:
1
Solution:
Correct answer is (a)