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Question
Mathematics
The number of solutions of the equation 32 tan 2 x+32 sec 2 x=81,0 ≤ x ≤ (π/4) is :
Q. The number of solutions of the equation
3
2
t
a
n
2
x
+
3
2
s
e
c
2
x
=
81
,
0
≤
x
≤
4
π
is :
2515
207
JEE Main
JEE Main 2021
Trigonometric Functions
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A
3
0%
B
1
50%
C
0
38%
D
2
13%
Solution:
(
32
)
t
a
n
2
x
+
(
32
)
s
e
c
2
x
=
81
⇒
(
32
)
t
a
n
2
x
+
(
32
)
1
+
t
a
n
2
x
=
81
⇒
(
32
)
t
a
n
2
x
=
33
81
In interval
[
0
,
4
π
]
only one solution