Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The number of solutions of the equation 2 θ- cos 2 θ+√2=0 is R is equal to
Q. The number of solutions of the equation
2
θ
−
cos
2
θ
+
2
=
0
is
R
is equal to ____
495
159
JEE Main
JEE Main 2022
Trigonometric Functions
Report Error
Answer:
1
Solution:
2
θ
−
cos
2
θ
+
2
=
0
⇒
cos
2
θ
=
2
θ
+
2
y
=
2
θ
+
2
Both graphs intersect at one point.