Question

The number of sodium atoms in $2$ moles of sodium ferrocyanide is

• A. $12\times 10^{23}$
• B. $26\times 10^{23}$
• C. $34\times 10^{23}$
• D. $48\times 10^{23}$

Answer 1

Answer: (D)

Formula of sodium ferrocyanide $N{a}_4\left[Fe(CN{)}_6\right]$ of suggests that it has four sodium atoms.

Number of $Na$ atoms

$=$ Number of moles $\times$ number of atoms per molecule $\times$ Avogadro number

$=2\times 4\times 6.023\times 10^{23}=48\times 10^{23}$