The number of sodium atoms in 2 moles of sodium ferrocyanide is

Question

The number of sodium atoms in 2 moles of sodium ferrocyanide is (A)  12× 1023  (B)  26× 1023  (C)  34× 1023  (D)  48× 1023

Tardigrade Admin · Accepted Answer

Formula Na4[Fe(CN)6] sodium Ferro cyanide suggests that it has four sodium atoms. Number of Na atoms = no. of moles × no. of atoms per molecule x Avogadro number =2× 4× 6.023× 1023 =48× 1023

Q. The number of sodium atoms in 2 moles of sodium ferrocyanide is

$12 \times 10^{23}$

$26 \times 10^{23}$

$34 \times 10^{23}$

$48 \times 10^{23}$

Formula $N a_{4} [F e (CN)_{6}]$ sodium Ferro cyanide suggests that it has four sodium atoms. Number of Na atoms = no. of moles $\times$ no. of atoms per molecule x Avogadro number $= 2 \times 4 \times 6.023 \times 10^{23}$ $= 48 \times 10^{23}$

Q. The number of sodium atoms in 2 moles of sodium ferrocyanide is

12×1023

26×1023

34×1023

48×1023

Formula Na4​[Fe(CN)6​] sodium Ferro cyanide suggests that it has four sodium atoms. Number of Na atoms = no. of moles × no. of atoms per molecule x Avogadro number =2×4×6.023×1023 =48×1023

$12 \times 10^{23}$

$26 \times 10^{23}$

$34 \times 10^{23}$

$48 \times 10^{23}$

Formula $N a_{4} [F e (CN)_{6}]$ sodium Ferro cyanide suggests that it has four sodium atoms. Number of Na atoms = no. of moles $\times$ no. of atoms per molecule x Avogadro number $= 2 \times 4 \times 6.023 \times 10^{23}$ $= 48 \times 10^{23}$