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Q.
The number of sodium atoms in 2 moles of sodium ferrocyanide is
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Solution:
Formula $ N{{a}_{4}}[Fe{{(CN)}_{6}}] $ sodium Ferro cyanide suggests that it has four sodium atoms. Number of Na atoms = no. of moles $ \times $ no. of atoms per molecule x Avogadro number $ =2\times 4\times 6.023\times {{10}^{23}} $ $ =48\times {{10}^{23}} $