Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The number of radial nodes and angular nodes for d-orbital can be represented as
Q. The number of radial nodes and angular nodes for d-orbital can be represented as
4044
207
Structure of Atom
Report Error
A
(n-2) radial nodes + 1 angular node = (n - 1) total nodes
22%
B
(n-1) radial nodes + 1 angular node = (n - 1) total nodes
22%
C
(n-3) radial nodes + 2 angular nodes = (n - l - 1) total nodes
27%
D
(n-3) radial nodes + 2 angular nodes = (n - l) total nodes
29%
Solution:
Total number of nodes = n - 1 For d-orbital, radial nodes = n - 3 and there are 2 angular nodes.
The number of angular nodes is given by l. i.e., for p, 1 angular node, for d , 2 angular nodes and so on.