Question

The number of possible enantiomeric pair(s) produced from the bromination of $I$ and $II$, respectively, are

• A. 0.1
• B. 1.0
• C. 0.2
• D. 1.1

Answer 1

Answer: (A)

Bromination of compound $I$ will give a meso product. So, will not have any enantiomer product, but bromination of compound $II$ gives a chiral compound, hence its two form $d$ and $l$ are possible, which are mirror images of each other and are non-superimposable. It’s other enantiomeric form will be

So, it will have one enantiomeric pair. Thus, correct option is (a).