Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The number of points where f(x)=|x2 - 3 |x| - 4| is non-differentiable is
Q. The number of points where
f
(
x
)
=
∣
∣
x
2
−
3
∣
x
∣
−
4
∣
∣
is non-differentiable is
3490
284
NTA Abhyas
NTA Abhyas 2020
Continuity and Differentiability
Report Error
A
1
9%
B
2
24%
C
3
50%
D
4
16%
Solution:
Graph of
f
(
x
)
=
∣
∣
x
2
−
3
∣
x
∣
−
4
∣
∣
is
From the graph, we see that
f
(
x
)
is non-differentiable at
x
=
0
,
−
4
,
4