The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 × 10-3 watt will be: ( h =6.6 × 10-34 Js )

Question

The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600 nm, when it delivers the power of 3.3 × 10-3 watt will be: ( h =6.6 × 10-34 Js ) (A) 1018 (B) 1017 (C) 1016 (D) 1015

Tardigrade Admin · Accepted Answer

The number of protons delivered per second is given by ( n / t )=( IA λ/ hc )=( P λ/ hc ) ⇒ ( n / t )=(3.3 × 10-3 × 600 × 10-9/3 × 108 × 6.6 × 10-34) ( n / t )=1016

Q. The number of photons per second on an average emitted by the source of monochromatic light of wavelength $600 nm$ , when it delivers the power of $3.3 \times 1 0^{- 3}$ watt will be : $(h = 6.6 \times 1 0^{- 34} J s)$

$1 0^{18}$

$1 0^{17}$

$1 0^{16}$

$1 0^{15}$

The number of protons delivered per second is given by
$\frac{n}{t} = \frac{I A λ}{h c} = \frac{P λ}{h c}$
$\Rightarrow \frac{n}{t} = \frac{3.3 \times 1 0 ^{- 3} \times 600 \times 1 0 ^{- 9}}{3 \times 1 0 ^{8} \times 6.6 \times 1 0 ^{- 34}}$
$\frac{n}{t} = 1 0^{16}$

Q. The number of photons per second on an average emitted by the source of monochromatic light of wavelength 600nm, when it delivers the power of 3.3×10−3 watt will be : (h=6.6×10−34Js)

1018

1017

1016

1015