Total number of permutations =2!9!
Number of those containing 'HIN' =7!
Number of those containing 'DUS' =2!7!
Number of those containing 'TAN' =7!
Number of those containing 'HIN' and 'DUS' =5!
Number of those containing 'HIN' and 'TAN' =5!
Number of those containing 'TAN' and 'DUS' =5!
Number of those containing 'HIN', 'DUS' and 'TAN' =3!
Required number =2!9!−(7!+7!+27!)+3×5!−3!=169194