The number of moles of oxygen obtained by the electrolytic decomposition of 108 g water is

Question

The number of moles of oxygen obtained by the electrolytic decomposition of 108 g water is (A) 2.5 (B) 3 (C) 5 (D) 7.5

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6a590b24c3ae2e0eda18b1c83041e2be-.png" /> ∵ 36 g of H 2 O produce 1 mole of oxygen ∴ 108 g of water will produce oxygen =(108/36)=3 mol

Q. The number of moles of oxygen obtained by the electrolytic decomposition of $108 g$ water is

2.5

3

5

7.5

$∵ 36 g$ of $H_{2} O$ produce $1$ mole of oxygen
$∴ 108 g$ of water will produce oxygen
$= \frac{108}{36} = 3 m o l$

Q. The number of moles of oxygen obtained by the electrolytic decomposition of 108g water is

2.5

3

5

7.5

∵36g of H2​O produce 1 mole of oxygen ∴108g of water will produce oxygen =36108​=3mol

Q. The number of moles of oxygen obtained by the electrolytic decomposition of $108 g$ water is

$∵ 36 g$ of $H_{2} O$ produce $1$ mole of oxygen
$∴ 108 g$ of water will produce oxygen
$= \frac{108}{36} = 3 m o l$