The number of moles of K 2 Cr 2 O 7 that will be needed to react with one mole of nitrite ion in acidic solution is

Question

The number of moles of K 2 Cr 2 O 7 that will be needed to react with one mole of nitrite ion in acidic solution is (A) (2/3) (B) (1/3) (C) (1/6) (D) (1/2)

Tardigrade Admin · Accepted Answer

meq. of K 2 Cr 2 O 7= meq. of NO 2- n1 × 6=1 × 2 n1=(1/3)

Q. The number of moles of $K_{2} C r_{2} O_{7}$ that will be needed to react with one mole of nitrite ion in acidic solution is

$\frac{2}{3}$

$\frac{1}{3}$

$\frac{1}{6}$

$\frac{1}{2}$

meq. of $K_{2} C r_{2} O_{7} =$ meq. of $N O_{2}^{-}$
$n_{1} \times 6 = 1 \times 2$
$n_{1} = \frac{1}{3}$

Q. The number of moles of K2​Cr2​O7​ that will be needed to react with one mole of nitrite ion in acidic solution is

32​

31​

61​

21​