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Q. The number of moles of $K _{2} Cr _{2} O _{7}$ that will be needed to react with one mole of nitrite ion in acidic solution is

Solution:

meq. of $K _{2} Cr _{2} O _{7}=$ meq. of $NO _{2}^{-}$
$n_{1} \times 6=1 \times 2$
$n_{1}=\frac{1}{3}$