The number of moles of hydroxide (OH-) ion in 0.3 litre of 0.005 M solution of Ba(OH)2 is:

Question

The number of moles of hydroxide (OH-) ion in 0.3 litre of 0.005 M solution of Ba(OH)2 is: (A) 0.0050 (B) 0.0030 (C) 0.0015 (D) 0.0075

Tardigrade Admin · Accepted Answer

Ba(OH)2 xrightarrowBa2++2OH- Thus 1 mole Ba(OH)2 gives 2 moles of hydroxide (OH-) ions. Hence, 0.3× 0.005 moles of Ba(OH)2 will give =0.3× 0.005× 2 = 0.0030 moles

Q. The number of moles of hydroxide $(O H^{-})$ ion in 0.3 litre of 0.005 M solution of $B a (O H)_{2}$ is:

0.0050

0.0030

0.0015

0.0075

$B a (O H)_{2} B a^{2 +} + 2 O H^{-}$ Thus 1 mole $B a (O H)_{2}$ gives 2 moles of hydroxide $(O H^{-})$ ions. Hence, $0.3 \times 0.005$ moles of $B a (O H)_{2}$ will give $= 0.3 \times 0.005 \times 2$ = 0.0030 moles

Q. The number of moles of hydroxide (OH−) ion in 0.3 litre of 0.005 M solution of Ba(OH)2​ is: