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Q. The number of moles of hydroxide $ (O{{H}^{-}}) $ ion in 0.3 litre of 0.005 M solution of $ Ba{{(OH)}_{2}} $ is:

JIPMERJIPMER 2001Equilibrium

Solution:

$ Ba{{(OH)}_{2}}\xrightarrow{{}}B{{a}^{2+}}+2O{{H}^{-}} $ Thus 1 mole $ Ba{{(OH)}_{2}} $ gives 2 moles of hydroxide $ (O{{H}^{-}}) $ ions. Hence, $ 0.3\times 0.005 $ moles of $ Ba{{(OH)}_{2}} $ will give $ =0.3\times 0.005\times 2 $ = 0.0030 moles