The number of molecules in 4.25 g of ammonia is approximately

Question

The number of molecules in 4.25 g of ammonia is approximately (A) 3 . 5 × 1023 (B) 0 . 5 × 1023 (C) 2.5 × 1023 (D) 1.5 × 1023

Tardigrade Admin · Accepted Answer

Given: Weight of ammonia =4 × 25 g . We know that 17 g of ammonia ( NH 3) contains 6 × 02 × 1023 molecules. Therefore number of molecules in 4 × 25 of NH 3= (6 × 02 × 1023 × 4 × 25/17) =1 × 50 × 1023

Q. The number of molecules in $4.25 g$ of ammonia is approximately

$3.5 \times 1 0^{23}$

$0.5 \times 1 0^{23}$

$2.5 \times 1 0^{23}$

$1.5 \times 1 0^{23}$

Given: Weight of ammonia $= 4 \times 25 g .$

We know that $17 g$ of ammonia $(N H_{3})$ contains $6 \times 02 \times 1 0^{23}$ molecules.

Therefore number of molecules in $4 \times 25$ of $N H_{3} = \frac{6 \times 02 \times 1 0 ^{23} \times 4 \times 25}{17}$

$= 1 \times 50 \times 1 0^{23}$

Q. The number of molecules in 4.25g of ammonia is approximately

3.5×1023

0.5×1023

2.5×1023

1.5×1023