Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The number of integral values of k for which the equation 7 cos x+5 sin x=2k+1 has a solution is
Q. The number of integral values of
k
for which the equation
7
cos
x
+
5
sin
x
=
2
k
+
1
has a solution is
2085
224
Jharkhand CECE
Jharkhand CECE 2013
Report Error
A
4
B
8
C
10
D
12
Solution:
We know that,
a
cos
θ
+
b
sin
θ
=
c
has one solution only.
∣
c
∣
≤
a
2
+
b
2
Then, for the given, equation, we must have
∣2
k
+
1∣
≤
74
⇒
−
74
<
2
k
+
1
<
74
⇒
−
8
<
2
k
+
1
<
8
∴
k
=
−
4
,
−
3
,
−
2
,
−
1
,
0
,
1
,
2
,
3
Thus, there are
8
values which will satisfy the above inequality