Question

The number of gram-molecules of oxygen which are present in $6.022\times {10}^{24}CO$ molecules is

• A. 10 g-molecule
• B. 5 g-molecule
• C. 1 g-molecule
• D. 0.5 g-molecule

Answer 1

Answer: (B)

Number of oxygen atoms = Number of CO molecules $=6.022\times {10}^{24}$ Number of oxygen molecules $=\frac{1}{2}\times$ No. of oxygen atoms $=\frac{1}{2}\times 6.022\times {10}^{24}=3.011\times {10}^{24}$ Number of g-molecules of oxygen $=\frac{3.011\times {10}^{24}}{6.022\times {10}^{23}}=$ 5 g-molecule