The number of geometrical isomers for [Pt(NH3)2Cl2] is

Question

The number of geometrical isomers for [Pt(NH3)2Cl2] is (A) Two (B) One (C) Three (D) Four

Tardigrade Admin · Accepted Answer

[pt(NH3)2 Cl2] <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/d227731b1ecf5d0399e2aa0cae932f9e-.jpeg" />

Q. The number of geometrical isomers for $[Pt (N H_{3})_{2} C l_{2}]$ is

Two

One

Three

Four

$[pt (N H_{3})_{2} C l_{2}]$

Q. The number of geometrical isomers for [Pt(NH3​)2​Cl2​] is

Two

One

Three

Four

[pt(NH3​)2​Cl2​]

Q. The number of geometrical isomers for $[Pt (N H_{3})_{2} C l_{2}]$ is

$[pt (N H_{3})_{2} C l_{2}]$